-2x^2+28x=98

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Solution for -2x^2+28x=98 equation: 



-2x^2+28x=98

We move all terms to the left:

-2x^2+28x-(98)=0

a = -2; b = 28; c = -98;
Δ = b2-4ac
Δ = 282-4·(-2)·(-98)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-28}{-4}=+7$

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